Consider the following four matrices from the vector space M2×3 of all 2 × 3 matrices:

A1 = 2 1 −3 2 −2 4 , A2 = 1 2 −12 −2 3 2 , A3 = 2 −2 0 −1 5 4 , A4 = 0 2 −4 1 −3 0 .

(a) Let vi denote the coordinate vector [Ai ]E relative to the basis E = 1 0 0 0 0 0 , 0 1 0 0 0 0 , 0 0 1 0 0 0 , 0 0 0 1 0 0 , 0 0 0 0 1 0 , 0 0 0 0 0 1 . Enter the coordinate vectors for A1, A2, A3, A4 into MATLAB.

(b) Use MATLAB to show that the coordinate vectors v1, v2, v3, v4 are linearly dependent.

(c) ? Express one of the matrices Ai as a linear combination of the other three. (Hint: first do the same for the coordinate vectors.)

step-by-step explanation:

divide, then simplify your answer.

1. make -15.66 ÷   5.8 a fraction. then divide.

2. simplify.  

3. final answer.  

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west