GEOMETRY HELP ASAP PLEASE BRAINLIEST (CLICK O THE PICTURE FOR QUESTION)

PA is a tangent, PBC is a secant, AOC is a diameter, AD and DC are chords

Angle APC = 57, Angle DC = 34

[measurements are in degrees]

(A) Arc BA = 66

Since AOC is a diameter, Arc AC is 180. Angle APC is equal to half the difference between BA and AC.

APC = 1/2 (AC - BA)

57 = 1/2 (180 - BA)

114 = 180 - BA

BA = 66

(B) Arc BD = 80

BD is 360 minus BA, AC, and DC.

BD = 360 - BA - AC - DC

BD = 360 - 180 - 66 - 34

BD = 80

(C) Angle ACD = 73

ACD is half of ABD, which is BA plus BD.

ACD = 1/2 (BA + BD)

ACD = 1/2 (66 + 80)

ACD = 1/2 * 146

ACD = 73

(D) Angle BED = 130

BED is the same as AEC, which is 180 minus ECA and EAC.

ECA is half BA, and EAC is half DC.

BED = 180 - 1/2 BA - 1/2 DC

BED = 180 - 1/2 * 66 - 1/2 * 34

BED = 180 - 33 - 17

BED = 130

(E) Angle PCA = 33

PCA is half BA

PCA = 1/2 BA

PCA = 1/2 * 66

PCA = 33

(F) Angle PAD = 73

PAD is half ABD, which is BA plus BD.

PAD = 1/2 (BA + BD)

PAD = 1/2 (66 + 80)

PAD = 1/2 * 146

PAD = 73

answer: c i think

step-by-step explanation:

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value