From a bag containing 6 gold balls, 3 silver balls, and 13 red balls, two are drawn at random. What is the probability that they are both red without replacement?

The probability is 26/77

Step-by-step explanation:

First, we calculate the probability of selecting a red ball.

To do this, we sum up the number of balls at first = 6 + 3 + 13 = 22 balls

The probability of selecting a red ball is 13/22

We now want to select two red balls without replacement.

The first probability is 13/22 while the second will be 12/21 since it is without replacement.

The final probability of both would thus be 13/22 * 12/21 = 156/462 = 26/77

i think the answer is fried chicken ; >

step-by-step explanation:

a. (14,375+570)(5.3) b. 158,417$

step-by-step explanation:

a. you are basically just setting up the equation. f= amount of debt hence 14,375. g= how much she is borrowing from her parents weekly hence 570 and t= the interest on her debt. creating the equation.

b.   14,375+570= 14,945

      14,945 x 5.3 = 79,208.5

      79,208.5 x 2(years) = 158,417(answer)