A researcher collects data on the number of times race horses are raced during their careers. The veterinarian finds that the average number of races a horse enters is 15.3, with a standard deviation of 6.8 in a sample of n = 25 horses.
A 95% confidence for µ, the average number of times a horse races, is given by .

95% confidence for µ, the average number of times a horse races

(12.493 , 18.107)

Step-by-step explanation:

Explanation:-

The veterinarian finds that the average number of races a horse enters is 15.3

The mean of the sample x⁻ = 15.3

Given standard deviation of the sample 'S' = 6.8

Given sample size 'n' = 25

Degrees of freedom = n-1 =25-1 =24

The tabulated value 't' = 2.064 at two tailed test 0.95 level of significance

95% confidence for µ, the average number of times a horse races

(15.3 - 2.80704 ,15.3 +2.80704)

(12.493 , 18.107)

Conclusion:-

95% confidence for µ, the average number of times a horse races

(12.493 , 18.107)

answer: (3,11) is your answer.

answer:   expression= p+p*d%

price reduction + sale price = $625

sale price: $p+$p*d%

where d% is the percentage of discount

step-by-step explanation:

original price = p

price went down by $150 price reduction $p*d%

sale price= $ 475

therefore the price before sale is: $625

and the expression that shows the price before sale is: p+p*d%