A ladder 25 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2 feet per second. How fast is the top of the ladder moving down the wall when its base is 7 feet from the wall?

6.86 ft per second

Step-by-step explanation:

Both the top and the bottom of the ladder will be moving at the same time.

Given that the base of the ladder is pulled away from the wall at a rate of 2 feet per second when its base is 7 feet from the wall. Then the time will be

Speed = distance/time

2 = 7/t

t = 7/2 = 3.5 seconds

Using pythagorean theorem to get the length L of the wall

L^2 = 25^2 - 7^2

L = 24

The ladder will move down the length at the same time.

Rate = 24/3.5

Rate = 6.86 ft/s

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

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