Choose the equation below whose axis of symmetry is x = 0. (1 point) Group of answer choices y = x2 + 2x y = x2 − 16x + 58 y = x2 + 2 y = x2 − 4x + 2

Step-by-step explanation:

Given the general form of quadratic equation , the axis of symmetry is derived using the equation

Given the equation

Next,

Next,

Lastly,

Clearly, is the equation whose axis of symmetry is x=0.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

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step-by-step explanation: