What is the equation of the circle with radius, r = 11 , and the center at (0, - 7)
A. x ^ 2 + (y + 7) ^ 2 = 121
B. (x + 7) ^ 2 + y ^ 2 = 121
C. (x - 7) ^ 2 + y ^ 2 = 11
D. x ^ 2 + (y - 7) ^ 2 = 11

A

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Given (h, k) = (0, - 7) and r = 11, then

(x - 0)² + (y - (- 7))² = 11², that is

x² + (y + 7)² = 121 → A

it could 14.28 but if its not that one then it has to be the 17 one. hope this ! : )

step-by-step explanation:

step-by-step explanation:

answers available in this download

(pearson%2c%25202012)%2520bbs.pdf& usg=aovvaw1obmtxnfghfgxhx0urh_je