1.which equation represents the axis of symmetry of the function y = –2x² + 4x –6?
y = 1
x = 1
x = 3
x = –3
2.what are the coordinates of the vertex of the graph of the function y = –x² + 6x –11?
(3, –2)
(3, 16)
(–3, –29)
(–3, –20)
3.what are the coordinates of the vertex of the graph of the function y = –3x² –12x + 3?
(–2, 29)
(2, –15)
(2, –9)
(–2, 15)

1-of the function y=-2x^2+4x-6? 
You gave no choices. 
y=-2(x^2-2x) -6 
y=-2(x^2-2x+1) -6+2 
y=-2(x-1)² -4 

x=1
2-x: use the same equation to find x, x=-(6)/2(-1)=-6/-2=3 Then use that x in the original equation: y=-(3)^2+6(3)-11=-2 Vertex is at (3,-2)
3- coordinate of vertex 

x = - b / 2 a 

In this case: 

x = - ( - 12 ) / [ 2 ( - 3 ) ] = 12 / - 6 = - 2 

y - coordinate: 

y = - 3 ( - 2 ) ^ 2 - 12 ( - 2 ) + 3 = 

- 3 * 4 + 24 + 3 = - 12 + 24 + 3 = 15 so its D

Idon’t know but you’ll figure it out