Use the quadratic formula to solve x^2-5x-2=0

we know

X = -b±(√b^2-4ac)

2a

NOW COMPARING X^2-5X-2=0 WITH AX^2+BX+C=0

WE GET

A=1

B=-5

C=-2

AGAIN,

X=-(-5)±√(-5)^2-4×1×(-2)

2×1

TAKING POSITIVE and negative you can find out answer

d

step-by-step explanation:

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