In a group of 60 students, 21 take math, 20 take psychologies, and 8 take both math and psychology. If one student is selected at random, find the probability that student takes math or psychology.

49/60

Step-by-step explanation:

They want the probability that one chosen at random will be taking math or psych. You will add up 21, 20, and 8 bc those students if theyre chosen r taken psych or math so the prob of randomly choosing one would be 49/60 which equals .816667 or .82

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

30

step-by-step explanation:

idk

i hope i