Mathematics, 26.04.2020 15:57 foreignev

Anyone who’s good at area please help
So
I need to find the SHADED area

The first one is for A)
The second one is B)

Anyone who’s good at area please help So I need to find the SHADED area The first one is for A) Th

Answers: 3

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Answer from: khuak877

a) 21

b) 78.5 - 28.3 - 12.57 = 37.63

Step-by-step explanation:

For the triangle, you want to use the formula 1/2 base times height and then subtract 2 time 2. For the circle, the formula is pi times the radius squared. Then, subtract the other circles using the same formula. I hope this helps! Please mark me brainliest because I have been scammed many times. Please and thank you.

Answer from: nini261

(a) 21 m squared

(b) 12π cm squared

Step-by-step explanation:

(a) Notice that in order to find the shaded area, we simply need to subtract the little square area from the big triangle's area.

The area of a triangle is: A = (1/2) * b * h, and here, b = 5 and h = 10. So, plugging these in, we have:

A = (1/2 ) * b * h

A = (1/2) * 5 * 10 = (1/2) * 50 = 25 m squared.

The area of a square is simply s * s, where s is the side length. Here, the side length is 2, so s = 2. Plugging this in, we get:

A = s * s

A = 2 * 2 = 4 m squared.

We subtract 4 from 25: 25 - 4 = 21 m squared.

(b) To find the area of the shaded region, we must find the total, big circle area and subtract both small circles' areas from it.

The area of a circle is denoted by: A = $\pi r^2$ , where r is the radius.

The second-smallest circle has a radius of 3, so r = 3. Plug this in:

A = $\pi r^2$

A = $\pi *3^2=9\pi$ cm squared

The smallest circle has a radius of 2, so r = 2. Plug this in:

A = $\pi r^2$

A = $\pi *2^2=4\pi$ cm squared

Notice that the sum of the diameters of the two small circles add up to the diameter of the big circle. The diameters of the two small circles are 3 * 2 = 6 and 2 * 2 = 4, so adding them together, we see that the big circle's diameter is 6 + 4 = 10. Since radius is half of diameter, the radius of the big circle is 10/2 = 5, so r = 5. Plug this in:

A = $\pi r^2$

A = $\pi *5^2=25\pi$ cm squared.

Now subtract each of the small circles' areas from this:

$25\pi -9\pi -4\pi =12\pi$

Thus, the shaded area is 12π cm squared.

Hope this helps!

Answer from: Quest

Ithink the answer is b

Answer from: Quest

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph

there is a hike in both the graphs so the graphs are increasing on their domain.x-intercept of log x and log 6x are differentthere is a vertical asymptote of both the graphs so there is no y-interceptas both the graphs are increasing so there is no horizontal asymptote

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Anyone who’s good at area please help
So
I need to find the SHADED area

Th...

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