Car A went 60 km in 5/6 hour while a car B went 54 km in 2/3 hour. Which car was faster? How many times faster?

Car B is faster

Car B is ×1.125 times faster

Step-by-step explanation:

Car A:

went 60 km in 5/6 hour

then

went 60/5 = 12 km in 1/6 hour

then

went 12 ×6 = 72 km in 6/6 = 1 hour

Car B:

went 54 km in 2/3 hour

then

went 54/2 = 27 km in 1/3 hour

then

went 27 × 3 = 81 km in 3/3 = 1 hour

81÷72 = 1.125

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;