Mathematics, 27.04.2020 01:37 swaise3300

0.105g of a given protein, containing unknown amounts of C H and O reacts with 02 to produce 0.257g of CO2 (44.01g/mol) and 0.035g of H2O (18.02g/mol), what is the empirical formula of the protein?

please explain

I just had this on an exam and had no clue how to do it, I need help

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Answer from: hannahbannana98

The answer to your question is C₃H₂O₁ or C₃H₂O

Step-by-step explanation:

Data

mass of protein = 0.105 g

elements = C, H, O

mass of CO₂ = 0.257 g

molar mass of CO₂ = 44.01 g/mol

mass of water = 0.035 g

molar mass of water = 18.02 g/mol

empirical formula = ?

Process

1.- Calculate the mass and moles of carbon

44 g of CO₂ 12 g of C

0.257 g of CO₂ x

x = (0.257 x 12)/44

x = 3.084/44

x = 0.07 g of Carbon

12 g of C 1 mol

0.07 g of C x

x = (0.07 x 1) / 12

x = 0.0058 moles of C

2.- Calculate the mass and moles of H

18 g of H₂O 2 g of H

0.035 g of H₂O x

x = (0.035 x 2) / 18

x = 0.0039 g of H₂

1 g of H 1 mol of H

0.0039 g of H x

x = 0.0039 moles of H

3.- Calculate the mass and moles of O₂

mass of O₂ = 0.105g - 0.07 - 0.0039g

= 0.0311 g of O₂

16 g of O₂ 1 mol

0.0311 f of O₂ x

x = (0.0311 x 1)/16

x = 0.0019 moles of O₂

4.- Divide by the lowest number of moles

Carbon = 0.0058 / 0.0019 = 3.0

Hydrogen = 0.0039 / 0.0019 = 2.0

Oxigen = 0.0019 / 0.0019 = 1

5.- Write the empirical formula

C₃H₂O₁ or C₃H₂O

Answer from: Quest

Cfhxr tu ivxdriizae6iklvd

Answer from: Quest

function 2 has a greater rate of change than function 1

function 2 has a greater y-intercept than function 1

step-by-step explanation:

$\newline{\text{the rate of change is change per unit time}}$ $\newline{\text{for (x,y), rate of change is }\frac{y_2-y_1}{x_2-x_1} \text{ or change in y divided by change in x}}$ $\newline{\text{for function 1, the cost goes up by 75-45=30 each time every hour}}$ $\newline{\text{that means that the slope of function 1 is 30 per hour}}$ $\newline{\text{for the 2nd function, 40 is added every hour. therefor, the slope is 40 per hour}}$ $\bigskip\newline{\text{since 40 per hour> 30 per hour, function 2 has a greater rate of change than function 1}}$ $\bigskip\newline{\text{the y intercept is the y value when x is 0}}$ $\newline{\text{for function 1, the y value when x is 0 is 45}}$ $\newline{\text{for function 2, the y value when x is 0 (or the flat rate) is 50}}$ $\newline{\text{since 50> 45, function 2 has a greater y intercept than funciton 1}}$ $\bigskip\bigskip\newline{\text{the answers are: }}$ $\newline{\text{ function 2 has a greater rate of change than function 1}}$ $\newline{\text{function 2 has a greater y-intercept than function 1.}}$

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0.105g of a given protein, containing unknown amounts of C H and O reacts with 02 to produce 0.257g...

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