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A cylinder container has a volume of 48 cm^3. Another container made out of the same material similar to the first container with a height that is two-thirds the height of the first container.
What is the volume of the second container?
Please show work thanks!

Step-by-step explanation:

Volume of first container = 48 cm³

πr²h = 48 cm³

Second container:

height = (2/3)h

Volume of second container=

=(2/3)* first container's volume      {πr²h = 48 cm³}

= 32 cm³

yes

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.