The initial point of a-> is (−1,6) , and its terminal point is (−3,−2) .

What is the value of ∥a-> ∥ ?

Enter your answer, as a simplified radical, in the box.

The answer should be 2sqrt17

Note that magnitude (||a||) is just the length of the vector.

the answer is b

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)