Determine the graph of the polar equation r=4/(1-1/2cosx(theta))

  see below

Step-by-step explanation:

We assume you want the graph of ...

A graphing calculator or spreadsheet is useful for this.

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You know cos(θ) = cos(-θ), so the graph is symmetrical about the x-axis. You can evaluate the function at a few points to find the general outline.

  r at 0° = 8

  r at 30° ≈ 7.05

  r at 45° ≈ 6.19

  r at 60° ≈ 5.33

  r at 90° = 4

  r at 120° = 3.2

  r at 135° ≈ 2.96

  r at 150° ≈ 2.79

  r at 180° ≈ 2.67

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.