A model rocket is launched from a roof into a large field. The path of the rocket can be
modeled by the equation y = -0.04x2+ 5.8x + 4.9, where x is the horizontal distance, in
meters, from the starting point on the roof and y is the height, in meters, of the rocket
above the ground. How far horizontally from its starting point will the rocket land?

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet