the question is attached in the image below

y = 3/2x-5/2

Step-by-step explanation:

We have two points so we can write the equation for the line. (-1,-4) and (3,2)

First we can find the slope by using

m= (y2-y1)/(x2-x1)

m = (2- -4)/(3 - -1)

   =(2+4)/(3+1)

   = 6/4

    = 3/2

Then put the slope into the slope intercept form of the equation

y= mx+b  where m is the slope and b is the y intercept

y = 3/2x+b

We will use the point (3,2) and substitute it into the equation to find b

2 = 3/2(3)+b

2 = 9/2 +b

Subtract 9/2 from each side

4/2 -9/2 = 9/2-9/2 +b

-5/2 = b

y = 3/2x-5/2

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.