Mr. Kaplan bought 11 tickets to the circus and spent $50. He bought child tickets for $4 each and bought adult tickets for $7 each. How many child and adult tickets did Mr. Kaplan buy?

9 child and 2 adult

Step-by-step explanation:

We can set up a systems of equations to solve this.

First equation:

We know he spent a total of $50 and child tickets are $4 while adult tickets are $7. We can set up an equation to represent this.

50=4c + 7a

c represents the number of child tickets bought and a represents the number of adult tickets bought.

Second Equation:

We know he bought 11 tickets, some of them are child tickets while others are for adults. We can represent this in an equation.

11= c + a

c represents the number of child tickets bought and a represents the number of adult tickets bought.

Put it all together:

The first step to solve one of the equations, isolating one of the variables. In this explanation, I will be solving the second equation first. I am going to solve it to be in terms of a, meaning I will isolate a.

Now that I have this equation, I will plug it in for a in the first equation and solve to isolate c.

Now we know that the number of child tickets bought was 9. To find out the number of adults tickets bought we plug 9 into another equation. I'm going to plug it into the second equation and solve to isolate a.

Now we are done, we know he bought 2 adult tickets and 9 child tickets.

"if it is my birthday, then it is snowing"