How do you represent the decimal 50 integer in binary?

50 = 5 × 10 + 0 × 1 (5 in the tens place, and 0 in units). 

We can write each place as a power of ten: 

50 = 5 × 10^1 + 0 × 10^0 

Similarly for hexadecimal and binary, but then using powers of 16 and 2 respectively. 
We need to find the digits of the hexadecimal form. Or in other words, we need to find a and b: 

50 = a × 16 + b × 1 

Simply divide 50 by 16 will get you a with some remainder, which is a multiple in units, and thus b: 

50 / 16 = 3 (=a), remainder 2. 
[2 / 1 = 2 (=b), remainder 0] 

Thus 50 in hexadecimal is "32". 

For binary, we need to do the division a couple of times more to find all digits. 

50 = a × 32 + b × 16 + c × 8 + d × 4 + e × 2 + f × 1 

50 / 32 = 1 (=a), remainder 18 
18 / 16 = 1 (=b), remainder 2 
2 / 8 = 0 (=c), remainder 2 
2 / 4 = 0 (=d), remainder 2 
2 / 2 = 1 (=e), remainder 0 
[0 / 1 = 0 (=f), remainder 0] 

We find that 50 in binary is "110010".

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step-by-step explanation:

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation: