In a three-game baseball series, the braves scored 5 runs in the first game, 4 runs in the second game, and 0 runs in the last game. the giants scored 6 runs in the first game, 1 run in the second game, and 3 runs in the last game. how many more runs did the giants score during the series than the braves?

a. 0; the braves scored 2 more runs.
b. 1 more run
c. 0; they scored the same amount.
d. 2 more runs

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.

to be honest i don't know but i need points so