Quadrilateral ABCD is a rhombus. Suppose m∠A decreases. Which of the following changes would also need to happen in order for ABCD to still be a rhombus?

none cuz there are no "following statements" regarding the question

step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

need more info

step-by-step explanation:

- click here to get an answer to your question ✍ 75 i will mark one of the angles formed by two

step-by-step explanation: