A cylindrical container with a radius of 5 cm and a height of 14 cm is completely filled with liquid. Some of the liquid from the cylindrical container is poured into a cone-shaped container with a radius of 6 cm and a height of 20 cm until the cone-shaped container is completely full. How much liquid remains in the cylindrical container?

The remaining liquid has a volume of 345.4 cm³.

Step-by-step explanation:

To solve this question we first need to calculate the volume of each container.

Cylindrical:

Volume = h*pi*r² = 14*3.14*(5)² = 1099 cm³

Cone:

Volume = (1/3)*h*pi*r² = (1/3)*20*3.14*(6)² = 753.6 cm³

Since the liquid from the cylinder was transfered to the cone until the latter was full, then what remains in the cylinder is it's original volume minus the cone volume. So we have:

remaining liquid = 1099 - 753.6 = 345.4 cm³

answer

d. 10

explanation

the distance from point y to wx is the height of the triangle.

using pythagoras theorem,

group similar terms to get,

this implies that,

take positive square root of both sides to get,

this implies that,