A utility company offers a lifeline rate to any household whose electricity falls below 240 kWh during a particular month. Let A denote the event that a randomly selected houshold in a certain community does not exceed the lifeline usage during January, and let B be the analogous event for the month of July (A and B refer to the same household). Suppose P(A) = 0.8, P(B) = 0.7, and P(A U B) = 0.9. Compute the following:

A. P(A intersection B)

A. 0.6

B. 0.3

Step-by-step explanation:

For part A we use the the general probability addition rule for the union of two events that states

P(A∪B) = P(A) + P(B) − P(A∩B)

Making P(A∩B) the subject of the equation above

P(A∩B) = P(A) + P(B) − P(A∪B)

P(A∩B) = 0.8 + 0.7 - 0.9

P(A∩B) = 0.6

B.

The description in terms of A and B is:

P(A but not B) + P(B but not A) = P(A∩B') + P(B∩A')

where A' is compliment of set A and B' is compliment of set B

The above description means either it exceeds in July or in January (exactly in one of the two months)

P(A∩B') = 0.8 − 0.6

P(B∩A') = 0.7 − 0.6

P(A∩B') + P(B∩A') = 0.3

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

4/6 = 2/3

so it should take 3/3 hours per man. so 9 hours is the answer 3*3 =9

step-by-step explanation: