If y varies directly as x^2, and y=2 when x=1, find y when x=10

The value of y when x = 10 is 200

Step-by-step explanation:

Here, we have y ∝ x^2 directly

⇒ y = k × x^2

where k is the constant of proportionality.

Now, let's find k from the first information set;

we can rewrite the equation as ;

k = y/x^2

k = 2/1^2 = 2/1 = 2

The value of y when x = 10 is as follows;

y = 2 × 10^2 = 2 × 100 = 200

3,000,540

step-by-step explanation:

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)