The value of a company’s piece of equipment decreases over time due to depreciation. The function y = 16,000(0.985)2t represents the value after t years.

a.) What is the average rate of change from year 1 to year 5?

b.) What is the average rate of change from year 5 to year 10?

c.) What conclusion about the value can we make based on these average rates of change?

THANK YOU FOR THE HELP!!!

A) 442

B) 385.9

C) The value is not constant. It depreciates

Step-by-step explanation:

Given the function

y = 16,000(0.985)^2t 

A) the average rate of change from year 1 to year 5 will be

When t = 1

y = 16,000(0.985)^2(1)

y = 15523.6

When t = 5

y = 16,000(0.985)^2(5)

y = 13755.69

Rate of change = (15523.6-13755.69) ÷ 4

Rate of change = 1767.91/4

Average of change = 442.0

B) the average rate of change from year 5 to year 10 will be

When t = 5

y = 16,000(0.985)^2t 

y = 16,000(0.985)^2(5)

y = 13755.69

When t = 10

y = 16,000(0.985)^2(10)

y = 11826.18

Average rate of change

= (13755.69 - 11826.18) ÷ 5

= 1929.51/2

= 385.9

C) The value is not constant. It depreciates

center= (-2,0)

radius= sqrt2/2

step-by-step explanation: