Find the volume of a right circular cone that has a height of 19 ft and a base with a diameter of 18.7 ft. Round your answer to the nearest tenth of a cubic foot.

1,793.7 ft³

Step-by-step explanation:

please see attached for reference

The volume of a right circular cone is given by

Volume, V = (1/3) πr²h   where,

V = volume of cone

r = radius = (1/2) diameter = 18.7/2 = 9.35 ft

h = height of cone = given as 19 ft

π = 3.142

Substituting the above values into the equation:

V = (1/3) πr²h

= (1/3) (3.142) (9.35)²(19)

= 1,739.6595 ft³

= 1,793.7 ft³  (nearest tenth)

the circle one

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2