A Statistics class is estimating the mean height of all female students at their college. They collect a random sample of 36 female students and measure their heights. The mean of the sample is 65.3 inches. The standard deviation is 5.2 inches. Use the T-distribution Inverse Calculator applet to answer the following question. What is the 90% confidence interval for the mean height of all female students in their school?

a. (56.5, 74.1)
b. (63.6, 67.0)
c. (63.8, 66.8)
d. (63.9, 66.7)

d. ( 63.9, 66.7)

Therefore at 90% confidence interval (a,b) = ( 63.9, 66.7)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 65.3

Standard deviation r = 5.2

Number of samples n = 36

Confidence interval = 90%

z(at 90% confidence) = 1.645

Substituting the values we have;

65.3+/-1.645(5.2/√36)

65.3+/-1.645(0.866667)

65.3+/-1.42567

65.3+/-1.4

= ( 63.9, 66.7)

Therefore at 90% confidence interval (a,b) = ( 63.9, 66.7)

idk bring the function back   im not smart

step-by-step explanation:

60°

step-by-step explanation:

the measure angle of c in an isosceles triangle abc is 60° because in isosceles triangle,the measures of all the angles is 60°.