A car traveled 462 miles per tankful of gasoline on the highway and 336 miles per tankful of gasoline in the city. If the car traveled 6 fewer miles per gallon in the city than on the highway, how many miles per gallon did the car travel in the city?

The car traveled 16 miles per gallon in the city

Step-by-step explanation:

Speed in highway = a miles per gallon

Speed in city = b miles per gallon

The car covers a miles with 1 gallon of fuel in the highway

It will cover 462 miles with 462/a gallons of fuel in the highway

The car covers b miles with 1 gallon of fuel in the city

It will cover 336 miles with 336/b gallons of fuel in the city

The car traveled 6 fewer miles per gallon in the city than on the highway

b = a - 6

Since the speed does not change with the fuel capacity of the car

462/a = 336/b

But b = a -6

462/a = 336/(a-6)

462(a-6) = 336a

462a - 2772 = 336a

462a - 336a = 2772

126a = 2772

a = 2772/126

a = 22 miles per gallon

The car travel 22 miles per gallon in the highway

In the city, b = a -6

b = 22 -6

b = 16 miles per gallon

The car traveled 16 miles per gallon in the city

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

true

step-by-step explanation: