A netball court is 30m by 15m. What is the distance from one corner of the court to the other

It would be 33.54m from one corner to the other.

A2+B2=C2

fill out A as 30

fill out B as 15

If we square these we get 900 and 225

Those added together gives you 1125

So now square root 1125. That gives you 33.54m, your answer.

Step-by-step explanation:

The distance from one corner to other corner of the court is the diagonal.

Use Pythagorean theorem.

(diagonal)² = (length)² + (width)²

                  = 30² + 15²

                  = 900 + 225

                  = 1125

diagonal = √1125

              =  33.54 m

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

69.64%

step-by-step explanation: