Eudora ran from her home to her secret laboratory at an average speed of 12 km/h12\text{ km/h} 12 km/h 12, start text, space, k, m, slash, h, end text . She then took one of her jetpacks and flew to her school at an average speed of 76 km/h76\text{ km/h} 76 km/h 76, start text, space, k, m, slash, h, end text . Eudora traveled a total distance of 120120 120 120 kilometers, and the entire trip took 22 2 2 hours. How long did Eudora spend running, and how long did she spend flying using her jetpack?

answer: an 8-foot rope is tied from the top of a pole to a

stake in the ground, as shown in the diagram

below

step-by-step explanation:

part a: 1.08

part b: 27.59

yes.. it's proven to be 36.

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.