In the right triangle shown angle Q is equal to 60 in QR is equal to two radical three how long is PQ

Step-by-step explanation:

Given a right angle triangle,

Where angle Q = 60°

<Q = 60°

And line QR is 2 radical 3.

2 radical 3 implies that 2 root 3

Therefore,

QR = 2√3

Then, we want to find PQ

Since you did not add the diagram and the question did not tell us where the right angle Is,

I will solve the question twice by choosing P as the right angle and also choosing R as the right angle

1. So, when P is right angle

So, check attachment for each of the diagram.

Using Cosine

Cos60 = adjacent / hypotenuse

Cos60 = x / 2√3

Cross multiply

x = 2√3 × Cos60

x = 2√3 × ½

x = √3

x = 1.732

Then, PQ = 2√3

2. When R is the right angle,

Again using cosine

Cos60 = adjacent / hypotenuse

Cos60 = 2√3 / x

Cross multiply

Cos60 × x = 2√3

x = 2√3 / Cos60

x = 2√3 / ½

x = 4√3

x = 6.93

Then, PQ = 4√3

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}