Henry invested his savings in two investment funds. The amount he invested in Fund A was $4000 less than the amount he invested in Fund B. Fund A returned a 7% profit and Fund B returned a 4% profit. How much did he invest in Fund B, if the total profit from the two funds together was $1590?

Amount invested in fund A is $12091

Amount invested in fund B is $16091

Step-by-step explanation:

Let the amount invested in fund A by Ali at 7% profit be x.

Thus, the amount invested in fund B at 4% profit will be; x + 4000

Now, we are told that the total profit from the two funds together was $1590.

Thus;

0.07x + 0.04(x + 4000) = 1590

0.07x + 0.04x + 160 = 1590

0.11x = 1590 - 160

0.11x = 1330

x = 1330/0.11

x ≈ $12091

So amount invested in fund A is $12091

Amount invested in fund B is;

$12091 + $4000 = $16091

£56

step-by-step explanation:

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)