Answer needed asap!! Graph a line with a slope of 3/4 that contains the point (2,-3)

The graph of the given line is required.

The required graph is attached below.

The slope of the line is

The point is

The equation is

Finding another point

Join the two points and the graph is drawn.

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By graphing the line, we have the equation y =

Step-by-step explanation:

What this question is asking us is to find the equation of the line with the value of the slope given in the question and also passing through the point in the question

For a straight line, the general equation can be represented as

y = mx + c

where m is the slope of the line and c is the y intercept. From the question, we have the value of the slope, what we have left to find is the value of the intercept. We find this by inserting the x, y and the slope value into the general equation of a straight line.

We have;

-3 = 3/4(2) + c

c = -3 - 6/4

c = -3-1.5 = -4.5

Thus, the equation of the line is;

y =

answer: what in the world is this

step-by-step explanation:

c > -10.55

step-by-step explanation: