![x=-3+\sqrt{27}\\ x=-3-\sqrt{27}](/tpl/images/0641/0005/8f066.png)
Step-by-step explanation:
Let's find our C value for the quadratic equation.
![(\frac{6}{2})^{2} = 9](/tpl/images/0641/0005/df385.png)
That is our C. Since we added 9 to one side, we have to do the same to the other. We get:
![x^{2} +6x + 9 = 18 + 9\\x^{2} +6x + 9 = 27](/tpl/images/0641/0005/a8971.png)
Now, lets form the left side as a binomial squared.
![(x+3)^{2} = 27](/tpl/images/0641/0005/fcfcc.png)
Let's square both sides now:
![x+3 = (+/-)\sqrt{27}](/tpl/images/0641/0005/39653.png)
Now, we subtract 3 from both sides to isolate the variable, X:
![x= -3(+/-)\sqrt{27}](/tpl/images/0641/0005/da9c0.png)
This means that the answers are:
![x=-3+\sqrt{27}\\ x=-3-\sqrt{27}](/tpl/images/0641/0005/8f066.png)
I do not understand your answers though. Answer A makes no sense, answer B is 221, answer C is 115, and answer D also does not make sense. If you could clarify this portion, maybe I can help you find your alphabetic answer