6(-5r – 4) – 2(r – 7s – 3)
In standard form
Please show step by step explanation

6(-5r-4)-2(r-7s-3)

Step-by-step explanation:

Final result :

 -2 • (16r - 7s + 9)

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 (6 • (-5r - 4)) -  2 • (r - 7s - 3)

Step  2  :

Step  3  :

Pulling out like terms :

3.1     Pull out like factors :

  -5r - 4  =   -1 • (5r + 4)

Equation at the end of step  3  :

 -6 • (5r + 4) -  2 • (r - 7s - 3)

Step  4  :

Step  5  :

Pulling out like terms :

5.1     Pull out like factors :

  -32r + 14s - 18  =   -2 • (16r - 7s + 9)

Final result :

 -2 • (16r - 7s + 9)

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180