Testing a bent coin, a coin manufacturer found that 6 out of 10 flips were heads. What is the probability of getting 2 tails using that bent coin?

6/10

9/25

4/10

4/25

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step-by-step explanation:

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5

22, 28, 34, 40, 46

b)   f(n) = 6n + 16

n = what is the number of the row ( 22 would be row 1) so if we replaced n with 1, we would get 22

c)   the 14th row will have 100 seats

(1)   (2)   (3)   (4)   (5)   (6)   (7)   (8)   (9)   (10) (11) (12) (13) (14)

22 | 28 | 34 | 40 | 46 | 52 | 58 | 64 | 70 | 76 | 82 | 88 | 94 | 100

c.

step-by-step explanation: it's not a. because 1/3 x 1/3 x 1/3 = 1/27 so that's not correct. | b. is also not correct because 7 x 7 1/3 is not actually 3 x 7 1/3 . and for d. multiplications are not additions so that left you with c. ( hope this out : d )