While bowling, Sarah made 5 strikes out of her last 18 frames. David made 9 strikes out his last 25 frames. What is the probability that they both get a strike on their next frame?

1/10 or 0.1

Step-by-step explanation:

Probability of occurrence of any event = number of favorable event by total /number of occurrence of event.

For Sarah

Given Number of frames = 18

Number of strikes made by her = 5

Therefore by using the above formula to get the probability of striking by Sarah will be 5/18.

For David

Given Number of frames = 25

Number of strikes made by him = 9

Therefore by using the above formula to get the probability of striking by David will be 9/25.

Since the event of Sarah and David are mutually independent i.e occurrence of one event does not impact the occurrence of other event.

Probability of occurrence of two mutually independent A and B event with Probability P(A) and Probability P(B) is given by P(A) * P(B).

Therefore probability that they both get a strike on their next frame are mutually independent event with probability 5/18 and 9/25 will be calculated by 5/18 * 9/25 = 1/(2*5) = 1/10.

my answer is$ 12

step-by-step explanation:

because 15 -2=12

maybe i can