A 1.30 L balloon is taken from room temperature (25.0° C) and placed into a freezer at -11.5° C. What
is its new volume? (Pressure is constant)

you would use (d.) the law of cosines or a^2 = b^2 + c^2 – 2bc(cos a)

, b^2 = a^2 + c^2 – 2ac(cos b), or c^2 = a^2 + b^2 - 2ab(cos c). you wouldn't use b. the law of sines as it is mostly effective when 1side and 2angles are given. a and c aren't the answer for they are the improper versions of the law of cosines. hope this is .

step-by-step explanation:

nope lol

step-by-step explanation: