Abhishek is 6 years older than Jagadish. Six years ago Abhishek was twice as old as Jagadish. Write down the situation in algebraic expression and find how old is each now?

Abhishek is 18 years, Jagadish is 12 years.

Step-by-step explanation:

Let Abhishek present age be y

Let Jagadish present age be z.

Abhishek is 6 years older than Jagadish. This can be written as:

y = z + 6 equation i

Six years ago, Abhishek was twice as old as Jagadish. This can be written as:

y - 6 = 2(z-6)

y - 6 = 2z - 12

y = 2z - 12 + 6

y = 2z - 6 equation ii

From equation i and equation ii, equate the values of y together. This will be:

z + 6 = 2z - 6

Collect like terms

2z - z = 6 + 6

z = 12 years

This means that Jagadish is 12 years.

From equation I

y = z + 6

y = 12 + 6

y = 18 years

Abhishek is 18 years

the factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24. hope this ! mark brainliest! you v much! : )

yes   because as the functions are graphed they eventually will intersect unless otherwise

step-by-step explanation: