A charge q1 = 5 μC, is at the origin. A second charge q2 = -3 μC is on the x-axis 0.8 m from the origin. The electric field at a point on the y-axis 0.5 m from the origin is:

Step-by-step explanation:

The electric field is given by:

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

at the point P(0,0.5m) you have both x ad y component of the electric field. For the particle q1 you have:

for the particle q2, it is necessary to compute the angle between the E vector and the axis, by using the distance y and x. Furthermore it is necessary to know the distance from q2 to the point P.

Finally, by adding E1 and E2 you obtain:

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.