A bag contains 23 coins, some dimes and some quarters. The total amount of money in the bag is $2.75. How many dimes and how many quarters are

in the bag?

X dimes

X quarters

Step-by-step explanation:

A bag contains 23 coins, some dimes and some quarters. The total amount of money in the bag is $2.75.

Let d be the  number of dimes

and q be the number of quarters

Total cons = 23

so equation becomes

1 dime = 10 cents

and 1 quarter =25 cents

The total amount of money in the bag is $2.75

2.75= 275 cents

solve the equation for d  and q

Plug in for q in second equation

combine like terms and subtract 575 from both sides

divide both sides by -15

d=20

so the number of dimes = 20

Number of quarter = 3

20 dimes

3 quarters

idk

step-by-step explanation:

answer: 0,6

step-by-step explanation:

this would make it the y intercept.