Most married couples have two or three personality preferences in common. Myers-

Briggs used a random sample of 375 married couples and found that 132 had three

preferences in common. Another random sample of 571 couples showed that 217 had

two personality preferences in common. Find a 90% confidence interval for the

proportion of married couples with three personality preferences in common compared

with the proportion of couples with two preferences in common. (Show your confidence

in interval notation and show your interpretation, which was larger?

The 90% confidence interval for the proportion of married couples with three personality preferences in common compared  with the proportion of couples with two preferences in common is (-0.081, 0.025).

Step-by-step explanation:

The (1 - α)% confidence interval for difference in proportion formula is,

The given information is:

n₁ = 375,

n₂ = 571,

X₁ = 132,

X₂ = 217.

Compute the sample proportion as follows:

For the 90% confidence level, the z-value is,

z₀.₀₅ = 1.645

*Use a z-table.

Compute the 90% confidence interval for the difference in proportion as follows:

The 90% confidence interval for the proportion of married couples with three personality preferences in common compared  with the proportion of couples with two preferences in common is (-0.081, 0.025).

This confidence interval implies that the true difference between the proportions lies in this interval with probability 0.90.

the answer would be c:   ax + b = ax + c

step-by-step explanation: