Let v⃗ 1=⎡⎣⎢⎢⎢0.50.50.50.5⎤⎦⎥⎥⎥, v⃗ 2=⎡⎣⎢⎢⎢0.50.5−0.5−0.5⎤⎦⎥⎥⎥, v⃗ 3=⎡⎣⎢⎢⎢0.5−0.5−0.50.5⎤⎦⎥⎥⎥. v→1=[0.50.50.50.5], v→2=[0.50.5−0.5−0.5], v→3=[0.5−0.5−0.50.5]. find a vector v⃗ 4v→4 in r4r4 such that the vectors v⃗ 1v→1, v⃗ 2v→2, v⃗ 3v→3, and v⃗ 4v→4 are orthonormal.

can you post a question that actually has the right graphics

Step-by-step explanation:

the answer is 3/5

step-by-step explanation:

first divide 24 divided by 8 because that is the least common multiple

then divide 40 by 8

then you will get 3/5.

what is the original number? you forgot to add it.