A circle has a diameter of 11cm

A square has a side length of 7cm

Use pythagoras’ theorem to show that the square will fit inside the circle without touching the edge of the circle.

Pleas help

The diagonal length of the square equals:

diagonal ^ 2 = 7^2 + 7^2

diagonal ^ 2 = 49 + 49

diagonal ^ 2 = 98

diagonal = 9.899 cm

The diagonal is smaller than the circle's diameter and so it will ft inside the circle.

Step-by-step explanation:

no he doesnt because "-16' is negatiive

step-by-step explanation:

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