In the function f(x)=(x-2)^2+4, the minimum value occurs when x is
A.)-2
B.)2
C.)-4
D.)4.

B

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

f(x) = (x - 2)² + k ← is in vertex form

with (h, k) = (2, 4)

Thus the minimum value is 4 when x = 2 → B

idk

step-by-step explanation: