What is the factor of this problem?
A.(x-2)(x-8)
B.(x-4)(x-4)
C.(x+2)(x+8)
D.(x+16)(x+1)

The answer is A. to solve this problem you need to get the -2 and -8 to multiply to your end number and add to your middle number. if you were to multiply -2 (-8) you would get 16 aka your back number! if you were to add -8+(-2) that would equal -10 aka your middle number. This is an easy trick to help with factoring! b cannot work because yes -4(-4) = 16 -4+(-4) =-8 not -10

The answer is all about the number 4