A city planner is rerouting traffic in order to work on a stretch of road. The equation of the path of the old route can be described as y = two fifths − 4. What should the equation of the new route be if it is to be perpendicular to the old route and will go through point (P, Q)?

(y - Q) = -5/2(x - P)

Step-by-step explanation:

The equation of the path of the old route is:

y = (2/5)x - 4

Two lines are perpendicular when the multiplication of their slopes is equal to minus one. So:

m*2/5 = -1

m = -1*5/2

m = -5/2

where m is the slope of the new route.

The point-slope form equation is:

(y - y1) = m(x - x1)

where (x1, y1) is a point on the line. Replacing with m = -5/2 and point (P, Q):

(y - Q) = -5/2(x - P)

y-Q= - 5/2(x-P)

Step-by-step explanation:

substitute (1,1) for point (P,Q) and graph the line. you’ll see that the correct answer ( y-Q= - 5/2(x-P)) is the only equation that goes through the point you chose (1,1) and is perpendicular to the line. hope this makes sense!

,xzgv

step-by-step explanation:

; oqirjg'