3n^2−2n−8 Factoring trinomials II

(3n + 4) (n-2)

Step-by-step explanation:

Are you asking to factor this 3n^2 - 2n -8 ?

If so the best way to do this problem  is with the X method.

                                     top:    3*(-8)

    left:  factor of 3*-8                             right:  factor of 3*-8

                                   bottom:  -2

try the factors  4 and -6  because   4*-6 =  3 *-8 = -24

Because   notice that  4 + -6 = -2

so:

    3n^2 -2n - 8  can be rewritten as    3n^2  -6n + 4n  - 8

We should first use Distributive property to factor:  3n^2  -6n + 4n  - 8

3n^2  -6n + 4n  - 8  =   3n (n - 2)  +  4(n - 2)

Now we factor by grouping here :   (3n + 4) (n-2)  

I factored out the group  (n-2)

Therefore:  (3n + 4) (n-2) = 3n^2 -2n - 8

given hc ∥ gd.¯¯¯¯¯¯which statement is true

step-by-step explanation:

∠cbe and ∠deb are same-side interior angles