What would be the coordinates at 315° if the coordinates at 135° are at (-square root 2/2, square root 2/2)?

We choose C

Step-by-step explanation:

the coordinates at 135° are at  (, )

As we can see, the x coordinate of the point is negative and the y coordinate of it is positive.

So this point is located at the quadrant ii

From  135 ° to 315°, it is rotated 180°

=> Each coordinate (x,y) is changed to (-x,-y)

= (, )  the new coordinate is located in quadrant iii

We choose C

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it